[" Let "y=y(x)" be the solution of the "],[" differential equation,"],[(dy)/(dx)+y tan x=2x+x^(2)tan x],[x in(-(pi)/(2),(pi)/(2))," such that "y(0)=1." Then "]

The solution of the differential equation (dy)/(dx)-y tan x=-2 sinx is -

Let y=y(x) be the solution of the differential equation, dy/dx+y tan x=2x+x^(2)tanx, x in(-pi/2,pi/2), such that y(0)= 1. Then

The solution differential equation (dy)/(dx)+y tan x=2x+x^(2)tan x is

Let y=y(x) be the solution of the differential equation, dy/dx+y tan x=2x+x^(2)tanx, x in(-pi/2,pi/2), such that y(0)= 1. Then (a) y'(pi/4)-y'(-pi/4)=pi-sqrt 2 (b) y'(pi/4)+y'(-pi/4)=-sqrt 2 (c) y(pi/4)+y(-pi/4)=-pi^(2)/2+2. (d) y(pi/4)-y(-pi/4)=sqrt 2

The solution of the differential equation (dy)/(dx) - 2y tan 2x = e^(x) sec 2x is

The Solution of the differential equation (dy)/(dx)=tan ((y)/(x))+(y)/(x) is

The solution of the differential equation (dy)/(dx)="tan"((y)/(x))+(y)/(x) is

The solution of the differential equation (dy)/(dx)="tan"((y)/(x))+(y)/(x) is

If y= y(x) is the solution of the differential equation dy/dx=(tan x-y) sec^(2)x, x in(-pi/2,pi/2), such that y (0)=0, than y(-pi/4) is equal to