The distance of the point `-i+2j+6k` from the straight line through the point `(2,3,-4)` and parallel to `6i+3j-4k` is-

The distance of the point having position vector -hat(i) + 2hat(j) + 6hat(k) from the straight line passing through the point (2, 3, –4) and parallel to the vector, 6hat(i) + 3hat(j) -4hat(k) is:

The distance of the point having position vector -hat(i) + 2hat(j) + 6hat(k) from the straight line passing through the point (2, 3, –4) and parallel to the vector, 6hat(i) + 3hat(j) -4hat(k) is:

the dist of two points -i+2j+6k from st line passes through 2i+3j+4k and parallel to vector 6i+3j-4k is

A : The vector equation of the line passing through the point 2i + 3j - 4k and parallel to the vector 6 + 3j - 4k is r = (2i + 3j - 4k) + t(6i + 3j - 4k). R : The vector equation of the line passing through the point a and parallel to the vector b is r = a + tb

The Cartesian equation of the line passing through the point 2i -j +4k and parallel to the vector i+j-2k is

The vector equation of the linepassing through the point i+j-k and parallel to the vector 2i+3j-k is

Find the distance of the point (-1,-2,3) from the Plane barr.(2i-3j+4k)=4