[" 9.Income "0-100100-200200-300300-400400-500500-600600-700700700700],[" Number "4],[" of persons "]

Find the mean deviation about the mean for the data : Income 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 per day Number 4 8 9 10 7 5 4 3 of persons

The data obtained for 100 shops for their daily profit per shop are as follows : {:(" Daily profit per shop (in ₹ ) ",0 - 100,100-200,200-300,300-400,400-500,500-600),(" Number of shops "," "12," "18," "27," "20," "17," "6):} Find the median profit per shop ?

The following table gives information regarding weekly income of labourer working at a dam site. {:("Income in (₹)",200-300,300-400,400-500,500-600,600-700),("No. of employees",150,160,130,180,120):} Calculate the (i) median (ii) lower quartile (iii) upper quartile (iv) 5th decile.

The size of land holdings of 380 families in a village is given below . Find the median size of land holdings. {:("Size of Land Holidings (in acres)","Less than 100",100-200,200-300,300-400,"400 and above" ),("Number of Families"," "40," " 89," "148," "64," "39):}

The table below shows the daily expenditure on food of 25 households in a locality. {:("Dail expenditure (in Rs)",100-150,150-200 , 200 - 250 , 250 -300,300-350),("Number of households",4,5,12,2,2):} Find the mean daily expenditure on food by suitable method.

Find out mode of the following series : {:("Income (Rs.)",110,120,130,140,150,160),("Nunber of Persons"," "2," "4," "8," "10," "5," "4):}

Number of persons living in a house is reported to be as under for 500 houses in a village. Find the median number of persons in a house in the village. {:("Number of Persons in a House",1,2,3,4,5,6,7,8,9,10),("Number of Houses",26,113,120,95,60,42,21,14,5,4):}