consider the triangle OAB in the xy- plane where `O=(0,0),A=(6,0), B=(sqrt(2),3)`. A square PQRS is inscribed in the square with P,Q on OA, R on AB and S on BO. Then the side of the square equals:

If O=(0,0), A=(1,0) and B=(1//2, sqrt3//2) then the centre of the circle for which the lines OA, Ab and BO are the tangents, is

Consider the triangle OAB where O(0,0),B(3,4) ,if the orthocentre of a triangle is H(1,4) and co-ordinates of A is (a,b) ,then a+b

Let A(0,0),B(3,0),C(2,1) then area of the square inscribed in the triangle such that,one side of the square is taken along bar(AB)

a square is inscribed in the circle x^(2)+y^(2)-10x-6y+30=0. One side of the square is parallel to y=x+3, then one vertex of the square is:

The area of Delta ABC with vertices A(a, 0), O(0, 0) and B(0, b) in square units is

Consider triangle AOB in the x-y plane, where A-=(1,0,0),B-=(0,2,0) and O-=(0,0,0) The new position of O, when triangle is rotated about side AB by 90^(0) can be a.((4)/(5),(3)/(5),(2)/(sqrt(5))) b.((-3)/(5),(sqrt(2))/(5),(2)/(sqrt(5))) c.((4)/(5),(2)/(5),(2)/(sqrt(5))) d.((4)/(5),(2)/(5),(1)/(sqrt(5)))

ABCD is square. P,Q,R,S are the mid points of the sides. If side of ABCD is 6cm. What is the area of PQRS