lf 12 tickets numbered `0,1,2,....11` are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to 12 is -

If 12 tickets numbered 0,1,2,...11 are placed in a bag,and three are drawn out,then the chance that the sum of the numbers on them is equal to 12 is -

if 6n tickets numbered 0,1,2,......6n-1 are placed in a bag and three are drawn out,show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0126n-1 are placed in a bag and three are drawn out,show that the chance that the sum of the numbers on them is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

if 6n tickets numbered 0,1,2,....... 6n-1 are placed in a bag and three are drawn out , show that the chance that the sum of the numbers on then is equal to 6n is (3n)/((6n-1)(6n-2))

In a bag there are three tickets numbered 1,2,3. A ticket is drawn at random and put back, and this is done four times. The probability that the sum of the numbers is even, is

In a bag there are three tickets numbered 1,2,3. A ticket is drawn at random and put back, and this is done four times. The probability that the sum of the numbers is even, is

A bag contains 4 tickets numbered 00,01,10 and 11. Four tickets are chosen at random with replacement,the probability that the sum of numbers on the tickets is 22 is

A bag contains 4 tickets numbered 00, 01, 10 and 11. Four tickets are chosen at random with replacement, the probability that the sum of numbers on the tickets is 22 is