[O_(2)" undergoes photochemical dissociation into one normal oxygen atom and one "],[" oxygen atom,"1.967" eV more energetic than normal.The dissociation of "O_(2)" into two "],[" normal atoms of oxygen requires "498kJ/mol" .The maximum wavelength effective for "],[" photochemical dissociation of "O_(2)" in ( "1eV=96.5kJ/mol)A^(0)" is "]

O_(2) undergoes photochemical dissocia tion into one normal oxygen atom one oxygen atom 1.967 eV more energetic than normal .The dissociation of O_(2) into two bnormal atoms of oxygen required 498 kJ mol^(-1) what is the maximum wavelength effective for photochemical dissociation of O_(2) ?

O_(2) undergoes photochemical dissocia tion into one normal oxygen atom one oxygen atom 1.967 eV more energetic than normal .The dissociation of O_(2) into two bnormal atoms of oxygen required 498 kJ mol^(-1) what is the maximum wavelength effective for photochemical dissociation of O_(2) ?

O_(2) undergoes photochemical dissociation into one normal oxygen atom and one excited oxygen atom. Excited oxygen atom is 1.967 eV more energetic than normal . The dissociation of O_(2) into two normal atoms of oxygen required 498 kJ mol^(-1) , what is the maximum wavelength effective for photochemical dissociation of O_(2) ?

O_(2) undergoes photochemical dissociation into one normal oxygen atom and one excited oxygen atom. Excited oxygen atom is 1.967 eV more energetic than normal . The dissociation of O_(2) into two normal atoms of oxygen required 498 kJ mol^(-1) , what is the maximum wavelength effective for photochemical dissociation of O_(2) ?

N_(2) undergoes photochemical dissociation into one normal N- atom and one N- atom having 0.1eV more energy than normal N- atom. The dissociation of N_(2) into two normal atom of N requires 289.5 KJ//mol energy. The maximum wavelength effective for photochemical dissociation of N_(2) in nm is P nm ( 1 eV = 96.5 KJ/mol). Find the value of (P)/(100) .

N_(2) undergoes photochemical dissociation into one normal N- atom and one N- atom having 0.1eV more energy than normal N- atom. The dissociation of N_(2) into two normal atom of N requires 289.5 KJ//mol energy. The maximum wavelength effective for photochemical dissociation of N_(2) in nm is P nm ( 1 eV = 96.5 KJ/mol). Find the value of (P)/(100) .

Ozone in the upper atmoshphere absorbs ultraviolet radiation which induces the following chemical reaction O_(3)(g)rightarrowO_(2)(g)+O(g) O_(2) produced in the above photochemical dissociation undergoes further dissociation into one normal oxygen atom (O) and more energetic oxygen atom O** . O_(2)(g) rightarrowO+O** (O**) has 1 eV more energy than(O) and normal dissociation energy of O_(2) is 480 kJ "mol"^(-1) . [1 eV/Photon =96 kJ "mol"^(-1) ] What is the maximum wavelength effective for the photochemical dissociation of O_(2) molecule

Ozone in the upper atmoshphere absorbs ultraviolet radiation which induces the following chemical reaction O_(3)(g)rightarrowO_(2)(g)+O(g) O_(2) produced in the above photochemical dissociation undergoes further dissociation into one normal oxygen atom (O) and more energetic oxygen atom O** . O_(2)(g) rightarrowO+O** (O**) has 1 eV more energy than(O) and normal dissociation energy of O_(2) is 480 kJ "mol"^(-1) . [1 eV/Photon =96 kJ "mol"^(-1) ] What is the maximum wavelength effective for the photochemical dissociation of O_(2) molecule

Ozone in the upper atmoshphere absorbs ultraviolet radiation which induces the following chemical reaction O_(3)(g)rightarrowO_(2)(g)+O(g) O_(2) produced in the above photochemical dissociation undergoes further dissociation into one normal oxygen atom (O) and more energetic oxygen atom O** . O_(2)(g) rightarrowO+O** (O**) has 1 eV more energy than(O) and normal dissociation energy of O_(2) is 480 kJ "mol"^(-1) . [1 eV/Photon =96 kJ "mol"^(-1) ] What is the maximum wavelength effective for the photochemical dissociation of O_(2) molecule