[1.25g" of a solid dibasic acid is completely "],[" neutralised by "25mL" of "0.25" molar "Ba(OH)_(2)],[" solution.Then calculate the molecular mass of "],[" the acid."]

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba(OH_(2)) solution. Molecular mass of the acid is:

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba(OH_(2)) solution. Molecular mass of the acid is:

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba (OH)_2 solution. Molecular mass of the acid is :

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba (OH)_2 solution. Molecular mass of the acid is :

The pH of 0.25 M Ba(OH)_2 solution is:

A solution containing 3.00 g of a monobasic organic acid was just neutralised by 40 mL of 05 N NaOH solution. Calculate the molecular weight of the acid.

1.26 g of a dibasic acid were dissolved in water and the solution made up to 200 mL. 20 mL of this solution were completely neutralised by 10 mL of N/5 NaOH solution. Calculate the equivalent mass and molecular mass of the acid.

0.45 g of a dibasic acid is completely neutralised with 100 ml N/10 NaOH . The molecular weight of acid is