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IF y' = y/x(log y - log x+1), then the solution of the equation is :

IF y' = y/x(log y - log x+1), then the solution of the equation is :

Suppose x,y,z>1 then least value of log(xyz)[(log x)/(log y log z)+(log y)/(log x log z)+(log z)/(log x log y)]

prove that x^(log y-log z)*y^(log z-log x)*z^(log x-log y)=1

Find the value of (x^(log y - log z))(y^(log z-log x))(z^(log x - log y))

Show that f(x, y)=x-y log y+y log x is a homogeneous function of x and y.

If y = log (log x) then (d^(2)y)/(dx^(2)) is equal to

If y = log (log x), then (d^(2)y)/(dx^(2)) is equal to

If u(x,y)=y log x+x log y, then u_(x)u_(y)-u_(x)log x-u_(y)log y+log x log y=