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x^(2)-25x-84...

`x^(2)-25x-84`

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x^(2)-19x+84

Show that (x+4),(x-3) and (x-7) are factors of x^(3)-6x^(2)-19x+84

(10x^(2)+15x+63)/(5x^(2)-25x+12)=(2x+3)/(x-5)

Find the domain of f(x) = sqrt(x^(2) - 25x + 144)

Find the domain of f(x) = sqrt(x^(2) - 25x + 144)

If x=3 and y=-1, find the values of each of the using identity: ((5)/(x)+5x)((25)/(x^(2))-25+25x^(2))

Factorise : (2x^(2)+5x)(2x^(2)+5x-19)+84

The equation 6x^5-25x^4+31x^(3)-31x^(2)+25x-6=0 is reciprocal equation of