[" If "y=y(x)" is the solution of the differential equation "x(dy)/(dx)+2y=x^(2)" satisfying "y(1)=1" ,then "16" y "(1/2)],[" is equal to "]

The solution of the differential equation (dy)/(dx)=(1+x)(1+y^2) is

If y=y(x) is the solution of the differential equation x(dy)/(dx)+2y=x^(2) satisfying y(1)=1 , then y(1/2) is equal to (7k)/16 . The value of k is___________________.

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

The solution of the differential equation dy/dx = (1+x)(1+ y^2) is -

The solution of the differential equation dy/dx = (1+x)(1+ y^2) is -

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :