`f(x)={(2^(x+2)-16)/(4^x-16), if x != 2 and k, if x=2` at `x=2`

If f(x)={(2^(x+2)-16)/(4^x-16) , if x!=2 , k if x=2 is continuous at x=2 , find k

If f(x)={(2^(x+2)-16)/(4^(x)-16), if x!=2,k if x=2 is continuous at x=2, find k

f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , x = 2 .

find the value of k, so that the function f(x)={((2^(x+2)-16)/(4^(x)-16)", if "x!=2),(k", if "x=2):} is continuous at x=2.

If f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , is 'conti nuous' at x = 2 . then find 'k'.

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2k,quad if x=2 is continuous at x=2, find k

Find the value of 'k', such that the function : f(x) = {:{(2x^(x+2)-16)/(4^x -16), if x ne2),(k, if x =2):} is continuous at x =2

If f(x)={(2^(x+2)-16)/(4^x-16),if x!=2k ,if f(x) is continuous a t x=2, find k

For what value of k, the function f(x)={(x^(2)-16)/(x-4), if x!=4 and k,quad if x= is continuous at x=4?