The tangent at an extremity (in the first quadrant) of latus rectum of the hyperbola `x^2/4-y^2/5=1` meets `x`-axis and `y`-axis at `A` and `B` respectively. Then `(OA)^2- (OB)^2,` where `O` is the origin, equals:

The tangents at an extremity (in the first quadrant ) of latus rectum of the hyperbola (x^(2))/( 4) - ( y^(2))/( 5)=1 meets x-axis and y- axis at A and B respectively . Then (OA)^(2) - (OB) ^(2) , where O is the origin , equals

Find the latus-rectum of the hyperbola x^2−4y^2=4

The latus rectum of the hyperbola x^2/9-y^2/16=1 is _____.

The latus rectum of the hyperbola 3x^(2)-2y^(2)=6 is

The tangent at an extremity of latus rectum of the hyperbola meets x axis and y axis A and B respectively then (OA)^(2)-(OB)^(2) where O is the origin is equal to

The length of the latus rectum of the hyperbola x^(2) -4y^(2) =4 is

The length of the latus rectum of the hyperbola x^(2) -4y^(2) =4 is

The length of the latus rectum of the hyperbola 3x ^(2) -y ^(2) =4 is

The length of the latus rectum of the hyperbola 3x ^(2) -y ^(2) =4 is