Home
Class 12
CHEMISTRY
[" 5.The equilibrium constant of the rea...

[" 5.The equilibrium constant of the reaction: "],[Cu(s)+2Ag^(+)(aq,)rarr Cu^(+)2(aq,L)+2Ag(s)],[E^(@)=0.46V" at "298K" is "],[[" (1) "2.0times10^(10)," (2) "4.0times10^(10)],[" (3) "4.0times10^(15)," (4) "2.4times10^(10)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The equilibrium constent of the reaction. Cu(s)+2Ag(aq). Leftrightarrow Cu^(2+) (aq.)+2Ag(s) E^(@)=0.46" V at 298 K is"

The equivalent constant of the reaction: Cu(s)+2Ag^(+)(aq.) rarr Cu^(2+)(aq.)+2Ag(s) E^(@)=0.46 V at 298 K ,is:

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag^(+)(aq)rarr Cu^(2+)(aq)+2Ag(s): E_("cell")^(@)=0.46V

The equilbrium constant for the reaction : Cu + 2 Ag^(+) (aq) rarr Cu(2+) (aq) +2 Ag, E^@ = 0. 46 V at 299 K is

Calculate the equilibrium constant for the reaction Cu(s)+2Ag+(aq)rarrCu^(+2)(aq)+2Ag(s),E_("cell")^(@)=0.46V .

Calculate the equilibrium constant of the reaction: Cu(s) + 2Ag^+(aq) → Cu^(2+) (aq) + 2Ag(s) E^o(cell) = 0.46 V

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V