" (xii) "(sec theta+tan theta)/(cosen theta+cot theta)=(csc theta-cot theta)/(sec theta-tan theta)

(sec theta+tan theta)/(csc theta+cot theta)=(csc theta-cot theta)/(sec theta-tan theta)

Prove (sec theta+tan theta)/(cos ec theta+cot theta)=(cos ec theta-cot theta)/(sec theta-tan theta)

(sec theta+tan theta)/(sec theta-tan theta)+(sec theta-tan theta)/(sec theta+tan theta)

( sec theta + tan theta )/("cosec " theta + cot theta ) -(sec theta - tan theta )/( " cosec" theta - cot theta )=

If (sec theta-tan theta)/(sec theta+tan theta)=3/5 , then the value of (cosec theta+cot theta)/(cosec theta-cot theta) is: यदि (sec theta-tan theta)/(sec theta+tan theta)=3/5 ,है, तो (cosec theta+cot theta)/(cosec theta-cot theta) का मान क्या होगा ?

(1/(cos theta)-1/(sin theta))+1/(cosec theta-cot theta)-1/(sec theta+tan theta) =?

Prove that (tan theta)/(1-cot theta)+(cot theta)/(1-tan theta)=1+sec theta+tan theta

Prove that (i) (1)/(("cosec" theta- cot theta ))=("cosec" theta + cot theta) (ii) ((sec theta - tan theta))/((sec theta + tan theta))=(1+ 2tan^(2) theta - 2 sec theta tan theta)

(tan theta)/(sec theta+1)+(cot theta)/(csc theta+1)=csc theta+sec theta-csc theta sec theta

x=sec theta-tan theta, y=cosec theta+cot theta, then