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(2x+5y)^(2)...

(2x+5y)^(2)

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If x/y=13/6 then find the value of (2x^2+5y^2)/(2x^2-5y^2)

Find the product of the following binomials: ((2)/(3)x^(2)+5y^(2))((2)/(3)x^(2)+5y^(2))

Evaluate : (v) (4x^(2) - 5y^(2) ) (4x^(2) + 5y^(2) )

If (4x^2-3y^2):(2x^2+5y^2)=12:19 then x:y=

The midpoint of the chord 4x+5y-13=0 of the ellipse 2x^(2)+5y^(2)=20 is

(x-2y)^(2)-5(x-2y)+6=0

The equation of the chord of the ellipse 2x^(2)+5y^(2)=20 which is bisected at the point (2,1) is

If (2x-5y)^3-(2x+5y)^3=y[Ax^2+By^2] , then what is the value of (2A-B) ?

If (3x-5y)/(3x+5y) = 1/2 . Then find the value of (3x^(2)-5y^(2))/(3x^(2) + 5y^(2)) .

Simplify : (2x+y)^(5)-5y(2x+y)^(4)+10y^(2)(2x+y)^(3)-10y^(3)(2x+y)^(2)+5y^(4)(2x+y)-y^(5)