" (ii) "a_(1)=4,a_(n+1)=2na_(n)

Write the first six terms of following sequence : a_(1)=4,a_(n+1)=2na_(n) .

Define a sequence (a_(n)) by a_(1)=5,a_(n)=a_(1)a_(2)…a_(n-1)+4 for ngt1 . Then lim_(nrarroo) (sqrt(a_(n)))/(a_(n-1))

If a_(1) = 4 and a_(n + 1) = a_(n) + 4n for n gt= 1 , then the value of a_(100) is

Find the next five terms of each of the following sequences given by: a_(1)=1,a_(n)=a_(n-1)+2,n>=2a_(1)=a_(2)=2,a_(n)=a_(n-1)-3,n>2a_(1)=-1,a_(n)=(a_(n-1))/(n),n>=2a_(1)=4,a_(n)=4a_(n-1)+3,n>1

The sequence a_(1),a_(2),a_(3),a_(4)...... satisfies a_(1)=1,a_(2)=2 and a_(n+2)=(2)/(a_(n+1))+a_(n),n=1,2,3... If 2^(lambda)a_(2012)=(2011!)/((1005!)^(2)) then lambda is equal to

Let a_(1)=1,a_(n)=n(a_(n-1)+1 for n=2,3,... where P_(n)=(1+(1)/(a_(1)))(1+(1)/(a_(2)))(1+(1)/(a_(3)))...*(1+(1)/(a_(n))) then Lt_(n rarr oo)P_(n)=

If a_(n+1)=a_(n-1)+2a_(n) for n=2,3,4, . . . and a_(1)=1 and a_(2)=1 , then a_(5) =

The Fibonacci sequence is defined by 1=a_(1)=a_(2) and a_(n)=a_(n-1)+a_(n-2),n>2 Find (a_(n+1))/(a_(n)),f or n=5