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3/5x-(2x-1)/3>1 2x - 1...

`3/5x-(2x-1)/3>1 2x - 1`

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2x-1/3=1/5-x

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)

3 ((3x-1) / (2x + 3))-2 ((2x + 3) / (3x-1)) = 5, x! = (1) / (3),-(3) / (2) )

3 ((3x-1) / (2x + 3))-2 ((2x + 3) / (3x-1)) = 5, x! = (1) / (3),-(3) / (2) )

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

Solve : (5x+2)(5x-3)(2x-1)(2x+1)=2.

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

determine whether following are polynomial or not 2x^2/3−3x^2/2+x-5 (2) x^3/2-3x^2+5x^(1/2)+x-1

The constant term in the expansion of |(3x +1,2x-1,x+2),( 5x-1, 3x+2,x+1),(7x-1,3x+1,4x-1)| is