`2+1=0`

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If adj [(1,0,2),(-1,1,-2),(0,2,1)]=[(5,a,-2),(1,1,0),(-2,-2,b)] , then find a ,b

adj- [{:( 1,0,2),(-1,1,-2),(0,2,1):}]=[{:(5,a,-2),(1,1,0),(-2,-2,b):}] , then [a, b] is equal to-

If [(1,2,1)][(1,2,0),(2,0,1),(1,0,2)] [(0),(2),(x)] = 0 , then the value of x is

for what values of x: [1" "2" "1][{:(1,2,0),(2,0,1),(1,0,2):}][{:(0),(2),(x):}]=0?

for what values of x: [1" "2" "1][{:(1,2,0),(2,0,1),(1,0,2):}][{:(0),(2),(x):}]=0?

for what values of x: [1" "2" "1][{:(1,2,0),(2,0,1),(1,0,2):}][{:(0),(2),(x):}]=0?

For what values of x:[[1, 2, 1]] [[1, 2, 0],[ 2, 0, 1],[ 1, 0, 2]][[0],[ 2],[ x]]=0 ?

For what values of x : [[1, 2, 1]][[1 ,2 ,0],[ 2, 0, 1],[ 1, 0, 2]][[0],[ 2],[x]]=O ?

Find the value of 'x' such that : [ 1 2 1] {:[(1,0,2),(0,2,1),(2,0,3)][(x),(4),(1)]=O