[(v)t^(2)-15],[" olvnomial each with th "]

When x=(5)/(2), numerically greatest term in the expansion of (3+2x)^(15) is (A)6th(B)8th (C) 10th(D)12th

For a 1st order reaction, time taken for half of the reaction to complete is t, whereas that for3/4 th of the reaction to complete is t_(2) . How are t_(1) and t_(2) , related to each other?

The numbers 1,3,6,10,15,21,28"..." are called triangular numbers. Let t_(n) denote the n^(th) triangular number such that t_(n)=t_(n-1)+n,AA n ge 2 . If (m+1) is the n^(th) triangular number, then (n-m) is

The numbers 1,3,6,10,15,21,28"..." are called triangular numbers. Let t_(n) denote the n^(th) triangular number such that t_(n)=t_(n-1)+n,AA n ge 2 . If (m+1) is the n^(th) triangular number, then (n-m) is

The numbers 1,3,6,10,15,21,28"..." are called triangular numbers. Let t_(n) denote the n^(th) triangular number such that t_(n)=t_(n-1)+n,AA n ge 2 . If (m+1) is the n^(th) triangular number, then (n-m) is

If for a reaction t_(x//y) represents time required for (x)/(y) th fraction of reactant to react then identify the correct option for a first order reaction : Statement-I : t_(3//4)=t_(1//2)xx2 Statement-II : t_(15//16)=t_(1//2)xx4 Statement-II : t_(7//8)=t_(3//4)xx2 Statement-IV : t_(15//16)=t_(3//4)xx3