" 1.) "((x)/(x+1))^(2)-5((x)/(x+1))+6=0

Solve the following equations. (x/(x +1))^2 - 5 (x/(x+1)) div 6 =0, x ne -1 .

(iv) ((2x+1)/(x+1))^(4)-6((2x+1)/(x+1))^(2)+8=0

(x^(2)-(x+1)(x+2))/(5x+1)=6

Solve (x^(2)+(1)/(x^(2)))-5(x+(1)/(x))+6=0," when "x ne0

If x,y,z in R , then the value of determinant |((5^(x)+5^(-x))^(2) , (5^(x)-5^(-x))^(2),1),((6^(x)+6^(-x))^(2),(6^(x)-6^(-x))^(2), 1),((7^(x)+7^(-x))^(2),(7^(x)-7^(-x))^(2),1)| is

Determine the values of x satisfying the following equalities: (a) |(x-1)/(x+1)|=(x-1)/(x+1) (b) |x^(2)-5x+6|=-(x^(2)+-5x+6)

((x+3)(x^(2)-5x+6))/((x^(2)+x+1)(x-4))<=0