`sina+sin2a+sin3a+...+sin na= (sin(((n+1)a)/2)sin((na)/2))/(sin(a/2))`

sin a + sin2a + sin3a + ... + sin na = (sin (((n + 1) a) / (2)) sin ((na) / (2))) / (sin ((a) / (2 )))

sin x + sin2x + sin3x + ... + sin nx = (sin ((n + 1) / (2)) x (sin (nx)) / (2)) / (sin ((x) / (2)) )

sin A+sin3A+...+sin(2n-1)A=(sin^(2)nA)/(sin A)

sin x+sin3x+...+sin(2n-1)x=(sin^(2)nx)/(sin x)

sin x+sin3x+.......sin(2n-1)x=(sin^(2)nx)/(sin x)

In DeltaABC , prove that: a) (sin2A + sin2B + sin2C)/(sinA+sinB+sinC) = 8sin(A/2) sin(B/2)sin(C/2)

Prove that , sin theta + sin 2theta + ……+ sin n theta = ( (sin( n theta/(2)) sin ((n+1)/(2))theta))/(sin theta/2) , for all n in N .

Statement-1: sin10^(@)+sin120^(@)+....+sin350^(@)=0 Statement-2: sin alpha+sin (alpha+beta)+....+sin(alpha+(n-1)beta)=(sin(alpha+((n-1)beta)/(2))sin((nbeta)/(2)))/(sin((beta)/(2))), beta ne 2npi.

If A+B+C=pi , prove that : (sin 2A+sin 2B + sin 2C)/(sinA+sinB+sinC) = 8 sin(A/2) sin(B/2) sin(C/2)

If A+B+C=180^(@), (sin 2A+sin 2B+sin2C)/(sinA+sinB+sinC)=k sin. (A)/(2) sin. (B)/(2) sin. (C)/(2) then the value of 3k^(3)+2k^(2)+k+1 is equal to