A dip needle lies initially in the magne...

A dip needle lies initially in the magnetic merdian when it shows an angle of dip `theta` at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip `theta^(')`. Then `tantheta^(')/tantheta` is

Similar Questions

Explore conceptually related problems

A dip circle lies initially in the magnetic meridian. If it is now rotated through angle theta in the horizontal plane, then tangent of the angle of dip is changed in the ratio:

A dip circle lying initially in the magnetic meridian is rotated through angle theta in the horizontal plane. The ratio of tangent of apparent angle of dip to true angle of dip is

The correct value of the dip angle at a place is 45^@ . The dip circle is rotated through 45^@ out of the magnetic meridian. The apparent angle of dip will be :

A dip circle is at right angle to the magnetic meridian. What will be its apparanet dip?

If a dip needle is suspended at an angle 30° to the magnetic meridian, it makes an angle of 45^@ with the horizontal. The real dip is

A dip circle is at right angles to the magnetic meridian. What will be the apparent dip ?

A dip needle lies initially in the magnetic merdian when it shows an angle of dip `theta` at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip `theta^(')`. Then `tantheta^(')/tantheta` is

Similar Questions

Recommended Questions