A semi-circular sheet of metal of diameter 28cm is bent into an open conical cup. Find the depth and capacity of cup.

A semi circular sheet of metal of diameter 28 cm is bent to form an open conical cup. Find the capacity of the cup.

A semi-circular sheet of metal of diameter 28 cm is bent into an open conical cup. The depth of the cup is approximately

A semicircular thin sheet of metal of diameter 30 cm is bent an open an conical cup is made. Find the capacity of the cup.

A semicircular sheet of diameter 28 cm is bent to form an open conical cup. Find the capacity of the cup. (Use sqrt3 = 1.732 )

A semicircular sheet of paper of diameter 28cm is bent to cover the exterior surface of an open conical ice-cream cup.The depth of the ice-cream cup is (a) 8.12cm (b) 10.12cm (c) 12.12cm (d) 14.12cm

A circular wire of diameter 42cm is bent in the form of a rectangle whose sides are in the ratio 6:5. Find the area of the rectangle.

The side of a square metal sheet is 14 cm. A circular sheet of greatest diameter is cut out from it and removed. Find the area of the remaining metal sheet. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Area of circular sheet =pir^(2)=(22)/(7)xx7xx7=154cm^(2) Area of square metal sheet = ("side")^(2)=(14)^(2)=196cm^(2) (B) Since the circular sheet has greatest diameter, diameter of the circle = side of the square = 14 cm. (C) therefore "Radius of the circle sjeet"=(14)/(2)=7cm (D) therefore "The area of the remaining metal sheet"="Area of the square metal sheet"-"Area of the circular sheet"=196-154=42cm^(2)

Find the surface area of a sphere of diameter: 28cm