If `[x+[x]]<=2`,then x belongs to:

Solve for x: |(x+9,x,x),(x,x+9,x),(x,x,x+9)|=0

If f(x)=|[x+lambda,x,x] , [x,x+lambda,x] , [x,x,x+lambda]| then f(12x)-f(x)=

(i) Find the value of a = [{x}] + [{-x}] + {[x]} + {[-x]} + {x} + {-x} (ii) Solve the equation 2x = [x] + {x}

(i) Find the value of a = [{x}] + [{-x}] + {[x]} + {[-x]} + {x} + {-x} (ii) Solve the equation 2x = [x] + {x}

If 5{x}=x+[x] and [x]-{x}=(1)/(2) when {x} and [x] are fractional and integral part of x then x is

If f (x) = |[a,x,x+1],[2x,x(x-1),x(x+1)],[3x(x-1),x(x-1)(x-2),x(x+1)(x-1)]| , then f (10) is equal to

Using properties of determinants solve the following for x, |{:(x+a,x,x),(x,x+a,x),(x,x,x+a):}|=0

Using Properties of determinants, solve the following for x: {:|(x+a,x,x),(x,x+a,x),(x,x,x+a)|=0