(x+2y^(3))dy=ydx

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))

(2x-10y^(3))dy+ydx=0

If the solution curve of the differential equation (2x-10y^(3))dy+ydx =0 , passes through the points (0, 1) and (2, beta) , then beta is a root of the equation :

Solve: ydx+(x-y^(3))dy=0

Solve: ydx-(x+2y^(2))dy=0

Solve the differential equation (2x-10y^3)dy+ydx,y ne 0