6. In the circuit shown, the value of / in ampere is [2012] 4Ω 4Ω Γη 4 Ω 4Ω 4 ν. 1.6 Ω b. 0.60 c. 0.4 d. 1.5

If log_(x)4=0.4, then the value of x is a.1 b.4 c.16d.32

In the circuit shown in fig the voltage across the 2 Ω resistor is 12V. What is the emf of the battery and the current thorugh the 6 Ω resistor?

In triangleABC , Delta=6 , abc=60 , r=1 Then the value of 1/a+1/b+1/c is nearly (a) 0.5 (b) 0.6 (c) 0.4 (d) 0.8

In triangleABC , Delta=6 , abc=60 , r=1 Then the value of 1/a+a/b+a/c is nearly (a) 0.5 (b) 0.6 (c) 0.4 (d) 0.8

If a/b=4/3, then the value of (6a+4b)/(6a-5b) is -1 (b) 3 (c) 4 (d) 5

If a+b+c=0a n da^2+b^2+c^2=1, then the value of a^4+b^4+c^4 is 1 b. 4 c. 1/2 d. 1/4

In /_ABC,Delta=6,abc=60,r=1 Then the value of (1)/(a)+(a)/(b)+(a)/(c) is nearly (a) 0.5(b)0.6(c)0.4 (d) 0.8

If a/b=4/3, then the value of (6a+4b)/(6a-5b) is (a) -1 (b) 3 (c) 4 (d) 5

Choose correct alternative. When two resistances are connected in parallel then the equivalent resistance is 6//5 Omega . When one of the resistances is removed then the effective resistance is 2 Omega . The resistance of the wire removed will be A. 3 Ω B. 2 Ω C. 3 / 5 Ω D. 6 / 5 Ω

A moving coil galvanometer allows a full scale current of 10^(-4) A. A series resistance of 2 Momega is required to convert the above galvonometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is: a) 500Ω b) 100Ω c) 200Ω d) 10Ω