" 42.If "sin2 theta=(3)/(4)" then "sin^(3)theta+cos^(3)theta" will be equal to "=

sin4 theta-sin2 theta=cos3 theta

cos^(3)theta sin 3theta + sin^(3)theta cos3theta=3/4

If 3sin theta+4cos theta=5 then 4sin theta-3cos theta is equal to

If 3cos theta+4cos theta=5 then 4sin theta-3cos theta is equal to

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If sin theta = 1/2 and theta is acute then (3 cos theta -4 cos^(3) theta) is equal to

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to