`sqrt(log_3 7) = x^sqrt(log_7 3)` find `x`

value of 7^[{sqrt(log_7 3)+ sqrt(log_14 3)}*2^sqrt(log_14 3)]/3^{sqrt(log_3 7)+sqrt(log_3 14)) is equal to:

Find the value of x satisfying the equation,sqrt((log_(3)3sqrt(3)x+log_(x)3sqrt(3)x)*log_(3)x^(3))+sqrt(((log_(3)(3sqrt(x)))/(3)+(log_(x)(3sqrt(x)))/(3))*log_(3)x^(3))=2

log_(3sqrt(7))2401

If 3^(((log_3 7))^x)=7^(((log_7 3))^x) , then the value of x will be

If 3^(((log_3 7))^x)=7^(((log_7 3))^x) , then the value of x will be

Find (dy)/(dx)(1)sqrt(log x)(2)sqrt(sec x)(3)sqrt(log_(a)x)