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[" Molecules of benzoic acid "(C_(6)H_(5)COOH)],[" dimerise in benzene."w'" 'g of the acid dissolved "],[" in "30g" of benzene shows a depression in "],[" freezing point equal to "2K" .If the percentage "],[" association of the acid to form dimer in the "],[" solution is "80," then w is : "],[" (Given that "K_(f)=5K" kg mol- "],[" benzoic acid "=122gmol^(-1))]

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Molecules of benzoic acid (C_(6)H_(5)COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30g of benzene shows a depression in freezing point equal to 2K. If the percentage association of the acid to form dimer in the solution is 80, then w is : (Given that K_(f)=5K Kg "mol"^(-1) Molar mass of benzoic acid =122 g "mol"^(-1) )

Molecules of benzoic acid (C_(6)H_(5)COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30g of benzene shows a depression in freezing point equal to 2K. If the percentage association of the acid to form dimer in the solution is 80, then w is : (Given that K_(f)=5K Kg "mol"^(-1) Molar mass of benzoic acid =122 g "mol"^(-1) )

2.44 g 'w' g of the benzoic acid dissolved in 30 g of benzene shows depression in freezing equal to 2K. If the percentage association of the acid to form polymer (C_(6)H_(5)COOH)_(n) in the solution is 80, then find numerical value of n. (Given that K_(f) = 5K kg mol^(-1) , Molar mass of benzoic acid = 122 g mol^(-1) )

2.44 g 'w' g of the benzoic acid dissolved in 30 g of benzene shows depression in freezing equal to 2K. If the percentage association of the acid to form polymer (C_(6)H_(5)COOH)_(n) in the solution is 80, then find numerical value of n. (Given that K_(f) = 5K kg mol^(-1) , Molar mass of benzoic acid = 122 g mol^(-1) )

2g of benzoic acid dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K. What is the percentage association of benzoic acid if it forms a dimer in solution ? ( K_(f) for benzene = 4.9 K kg "mol"^(-1) )

2 g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62 K. Molal depression constant for benzene is 4.9 K kg "mol"^(-1) . What is the precentage association of acid if it forms dimer in solution ?

2g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K .Molal depression constant for benzene is 4.9Kkgmol^(-1) .What is the percentage association of acid if it forms dimer in solution?

2g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K .Molal depression constant for benzene is 4.9Kkgmol^(-1) .What is the percentage association of acid if it forms dimer in solution?

5 . 0 g of phenol dissolved in 250 g of benzene shows a depression in freezing point equal to 0 . 70^(@) C. What is the percentage association of phenol ? ( K_(f) for benzene = 5.12 K kg. MOL^(-1) )