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In Delta ABC,median AD is perpendicular ...

In `Delta ABC`,median AD is perpendicular to median BE, if BC=6,AC=8 and `AB=xsqrt5`,then find x.

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Here, we can draw the diagram with the given details.
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In `Delta AOE`,
`(2x)^2+y^2 = 4^2=> 4x^2+y^2 = 16->(1)`
In `Delta BOD`,
`(2y)^2+x^2 = 3^2 => 4y^2+x^2 = 9->(2)`
Adding (1) and (2),
`5x^2+5y^2 = 25 => x^2+y^2 = 5`
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