The value of `K_(p)` for the reaction
`CO_(2)(g)+C(s)hArr2CO(g)`
is `3.0` bar at `1000 K`. If initially `P_(CO_(2)) = 0.48` bar, `P_(CO) = 0` bar and pure graphite is present then determine equilibrium partial pressue of `CO` and `CO_(2)` .

The value of K_(p) for the reaction, CO_(2)(g)+C(s)hArr2CO(g) is 3.0 at 1000K . If initially P_(CO_(2))=0.48 bar and P_(CO)=0 bar and pure graphite is present, calculate the equilibrium partial pressures of CO and CO_(2) .

K_p/K_c for the reaction: CO(g)+1/2O_2(g) hArr CO_2(g) is :

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

At 1,000 K in the reaction CO_(2) (g) + C(s) rarr 2CO(g) The value of P_(CO_(2)) =0.48" bar and" P_(CO) = 0 bar. Pure graphite is present. The equilibrium partial pressures of CO and CO_(2) are 0.66 bar and 0.15 bar respectively. Calculate K_(P) of the reaction.

At 1,000 K in the reaction CO_(2) (g) + C(s) rarr 2CO(g) The value of P_(CO_(2)) =0.48" bar and" P_(CO) = 0 bar. Pure graphite is present. The equilibrium partial pressures of CO and CO_(2) are 0.66 bar and 0.15 bar respectively. Calculate K_(P) of the reaction.