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" (ii) "((5^(2))^(3)times5^(4))-:5^(7)...

" (ii) "((5^(2))^(3)times5^(4))-:5^(7)

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5(1)/(7)times3(2)/(4)

3+6times(5+4)-:3-7

Simplify : a. [(3^(3))xx3^(4)]-:3^(4) b. 18^(6)-:3^(12) c. [(5^(6))^(9)xx(5^(15))^(5)]-[(5^(13))^(5)xx(5^(4))^(16)] d. (3^(5)xx10^(5)xx25)-:(5^(7)xx6^(5)) e. ((2)/(b))^(18)xxb^(12)xx(3^(4))^(3) f. [(2^(4))^(2)xx2^(12)]-:4^(2) g. 12^(8)-:3^(6) h. [(7^(7))^(8)xx(7^(9))^(5)]-[(7^(11))^(6)xx(7^(7))^(5)] i. (25^(2)xxp^(4)xxq^(8))-:(5^(3)xxp^(4)xxq^(7)) j. ((a)/(3))^(24)xx2^(8)xx(3^(6))^(4)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

((2)/(3))^(4)times((3)/(2))^(5)times((5)/(3))^(-2)times((3)/(5))^(-3)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

A real number (2^(2)times3^(2)times7^(2))/(2^(2)times5^(3)times3^(5)times7^(4)) will have

-(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(7)/(6)

Verify the following:- (ii) (-15)/(4)times((3)/(7)+(-12)/(5))=((-15)/(4)times(3)/(7))+((-15)/(4)times(-12)/(5)) .

Simplify (3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))