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(mu(0)varepsilon(0))^(-(1)/(2))(1)/(201)...

(mu_(0)varepsilon_(0))^(-(1)/(2))(1)/(201)pi r+(3)/(8)1

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Two charges,each equal to 2C can be placed so that the force between them equals to the weight of an object of mass 1kg .The distance between them is (take "g=10m/s^(2)" ) (10 pi varepsilon_(0))^(1/2), [1/(10 pi varepsilon_(0))^(1/2)], [1/10 pi varepsilon_(0)], [10 pi varepsilon_(0)]

A charge q_(1) is placed at the centre of a spherical conducting shell of radius "R" .Conducting shell has a total charge q_(2) .Electrostatic potential energy of the system is (A) (q_(1)^(2)+2q_(1)q_(2))/(8 pi varepsilon_(0)R) (B) (q_(2)^(2)+2q_(1)q_(2))/(8 pi varepsilon_(0)R) (C) (q_(1)^(2)+q_(1)q_(2))/(8 pi varepsilon_(0)R) (D) (q_(2)^(2)+q_(1)q_(2))/(8 pi varepsilon_(0)R)

[" 11.For the situation shown in the figure (assume "r>>" length of dipole) select the "],[" correct statement(s): "],[[" A) Force acting on the dipole is zero "],[" B) Force acting on the dipole is approximately "(pQ)/(4 pi varepsilon_(0)r^(3))],[" C) Torque acting on the dipole is approximately "(pQ)/(4 pi varepsilon_(0)r^(2))" in clockwise direction."],[" D) Torque acting on the dipole is approximately "(pQ)/(2 pi varepsilon_(0)r^(2))" in clockwise direction."]]

Let f(x)=tan^(-1)(1/2 tan2x)+tan^(-1)(cotx)+tan^(-1)(cot^3x) then (1) f((3 pi)/8)=pi (2) f(pi/8)=0 (3) f(pi/8) =pi (4) f((3pi)/8)=0

Find the accelerations of blocks A and B for the following cases. (A) mu_(1)=0 " and "mu_(2)=0.1" (P)" a_(A)=a_(B)=9.5m//s^(2) (B) mu_(2)=0 " and "mu_(1)=0.1 " (Q)"a_(A)=9m//s^(2), a_(B)=10m//s^(2) (C) mu_(1)=0.1 " and "mu_(2)=1.0 " (R)"a_(A)=a_(B)=g=10m//s^(2) (D) mu_(1)=1.0 " and "mu_(2)=0.1 " (S)" a_(A)=1, a_(B)=9m//s^(2)

If 2f(x^(2))+3f((1)/(x^(2)))=x^(2)-1x varepsilon R_(0) then f(x^(2)) is

Evaluate the following {:[(1,-1),(0,2),(2,3)] ([(1,0,2),(2,0,1)] - [(0,1,2),(1,0,2)])

8.The diagram shows a part of uniformly charged disc of radius R having surface charge density sigma .If electric potential at the center 0 is (1)/(N)times(sigma R)/(2 varepsilon_(0)) Then find N .