(x-3)/(-1)=(y-4)/(2)=(z-2)/(1)*(x+1)/(1)=(y+7)/(3)=(z+2)/(2)" and find the eq "

Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " and (x)/(1) = (y)/(2) = (z)/(3) (ii) (x - 3)/(2) = (y + 1)/(-3) = (z - 2)/(4) and (x + 2)/(2) = (y - 4)/(4) = (z + 5)/(2) are perpendicular to each other .

The lines (x)/(1)=(y)/(2)=(z)/(3)and(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

The lines (x)/(1)=(y)/(2)=(z)/(3) and (x-1)/(-2)=(y-2)/(-4)=(3-z)/(6) are

if the lines (x)/(1)=(y)/(2)=(z)/(3),(x-1)/(3)=(y-2)/(-1)=(z-3)/(4) and (x+k)/(3)=(y-1)/(2)=(z-2)/(h) are concurrent then

If the lines (x)/(1)=(y)/(2)=(z)/(3),(x-1)/(3)=(y-2)/(-1)=(z-3)/(4) and (x+k)/(3)=(y-1)/(2)=(z-2)/(h) are concurrent then

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Find the equation of line through (-4, 1,3) & parallel to the plane x+y+z=3 while the line intersects another line whose eqution is x+y-z=x+2y-3z+5 (a) (x+4)/(-3)=(y-1)/(-2)=(z-3)/(1) (b) (x+4)/(1)=(y-1)/(2)=(z-3)/(-3) (c) (x+4)/(-3)=(y-1)/(2)=(z-3)/(1) (d)

Find the equation of line through (-4, 1,3) & parallel to the plane x+y+z=3 while the line intersects another line whose eqution is x+y-z=x+2y-3z+5 (a) (x+4)/(-3)=(y-1)/(-2)=(z-3)/(1) (b) (x+4)/(1)=(y-1)/(2)=(z-3)/(-3) (c) (x+4)/(-3)=(y-1)/(2)=(z-3)/(1)