A body falling freely under gravity passes two points 30 m apart in 1 s. From what point above the upper point it began to fall? (Take g = `9.8 m s^(-2)`).

A body falling freely under the action of gravity passes 2 points 9 m apart vertically in 0.2 s. From what height above the higher point did it start to fall?

A body is falling freely under gravity. It passes two points A and B (A being higher than B) 20m apart vertically in 2s. Find the elevation of the point above A from where it began to fall.

A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : (i) the time to reach the ground . Take g = 9.8 m s^(-2) .

A ball is thrown up with a speed of 15 m//s . how high will it go before it begins to fall ? Take g=9.8 m//s^(2) .

A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g= 10 ms^(-2)

A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : the velocity with which it strikes the ground. Take g = 9.8 m s^(-2) .

A bullet of mass 20g is found to pass two points 30m apart in 4 s? Assuming the speed to be constant, find its kinetic energy?

A body released from rest to fall freely under gravity reaches the ground in 4 s. Then the height from which it is released is

A body of mass 1 kg falls from a height of 5 m How mcuh energy does it posses at any instant ?(Take g=9.8 m s^(-2) )