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There is a LCR circuit , If it is compar...

There is a LCR circuit , If it is compared with a damped oscillation of mass m oscillating with force constant k and damping coefficient 'b'. Compare the terms of damped oscillation with the devices in LCR circuit.

A

`L to m, C to (1)/(k),R to b`

B

`L to m , c to R to b`

C

`L to K, C to b, R to m`

D

`L to (1)/(m) ,C to (1)/(k),R to (1)/(b)`

Text Solution

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The correct Answer is:
To compare the terms of damped oscillation with the devices in an LCR circuit, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Damped Oscillation**: The equation for damped oscillation can be expressed as: \[ m \frac{d^2x}{dt^2} + b \frac{dx}{dt} + kx = 0 \] Here, \( m \) is the mass, \( b \) is the damping coefficient, and \( k \) is the force constant. 2. **Understanding the LCR Circuit**: In an LCR circuit, we can apply Kirchhoff's voltage law, which gives us: \[ -iR - L \frac{di}{dt} - \frac{Q}{C} = 0 \] where \( i \) is the current, \( R \) is the resistance, \( L \) is the inductance, and \( C \) is the capacitance. 3. **Relating Charge and Current**: The current \( i \) is related to charge \( Q \) by: \[ i = \frac{dQ}{dt} \] Thus, substituting \( i \) into the equation gives: \[ -R \frac{dQ}{dt} - L \frac{d^2Q}{dt^2} - \frac{Q}{C} = 0 \] 4. **Rearranging the LCR Equation**: Rearranging the equation leads to: \[ L \frac{d^2Q}{dt^2} + R \frac{dQ}{dt} + \frac{Q}{C} = 0 \] 5. **Identifying Corresponding Terms**: Now, we can compare the coefficients of the two equations: - From the damped oscillation equation, we have: - \( m \) corresponds to \( L \) - \( b \) corresponds to \( R \) - \( k \) corresponds to \( \frac{1}{C} \) 6. **Final Relationships**: Therefore, we can summarize the relationships as: - \( m \equiv L \) - \( b \equiv R \) - \( k \equiv \frac{1}{C} \) ### Conclusion: The relationships between the parameters of damped oscillation and the components of the LCR circuit can be summarized as: - Mass \( m \) is equivalent to inductance \( L \) - Damping coefficient \( b \) is equivalent to resistance \( R \) - Force constant \( k \) is equivalent to \( \frac{1}{C} \)
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