Let `(log_2(x))^2-4 log_2(x) -m^2-2m- 13=0` be an equation in x and `m in R`, then which of the following must be correct?

Consider the equation (log_2 x)^(2) -4 log_2 x - m^(2) - 2m -13=0 , m in R . Let the real roots the equation be x_1,x_2 such that x_1 lt x_2 . The sum of maximum value of x_1 and minimum value of x_2 is :

Solve : log_2 (4-x) = 4 - log_2 (-2-x)

Solve: log_2 (4/(x+3)) > log_2 (2-x)

Let x^(2)-(m-3)x+m=0(m in R) be a a quadratic equation.Find the value of m for which the roots

Consider the equation log _(2)^(2) x -4 log _(2)x-m^(2) -2m -13=0, m in R. Let the real roots of the equation be x _(1), x _(2) such that x _(1)lt x _(2). The sum of maximum value of, x _(1) and minimum value of x _(2) is :

Consider the equation log _(2)^(2) x -4 log _(2)x-m^(2) -2m -13=0, m in R. Let the real roots of the equation be x _(1), x _(2) such that x _(1)lt x _(2). The sum of maximum value of, x _(1) and minimum value of x _(2) is :

Consider the equation log_2 ^2 x- 4 log_2 x- m^2 -2m-13=0,m in R. Let the real roots of the equation be x_1,x_2, such that x_1 < x_2 .The set of all values of m for which the equation has real roots is (i) (-infty ,0) (ii) (0,infty) (iii) [1, infty) (iv) (-infty,infty)

Consider the equation log_(2)^(2)x-x-4log_(2)x-m^(2)-2m-13=0,m varepsilon R Let the real roots of the equation be x_(1),x_(2), such that x_(1)