`((2. 5xx2)/2)^2+(11)^2-1=?`

((6.4)^(2)-(5.4)^(2))/((8.9)^(2)+8.9xx2.2+(1.1)^(2))=

Evaluate : ((6.4)^(2)-(5.4)^(2))/((8.9)^(2)+(8.9xx2.2)+(1.1)^(2))

(-11)^5xx(-11)^2

5.2 xx 2.1

Evaluate each of the following: (i)\ (2/(11))^4\ xx\ \ ((11)/3)^2\ xx\ \ (3/2)^3 (ii)\ (1/2)^5\ xx\ ((-2)/3)^4xx\ (3/5)^(-1)

Simplify : (8^(3a)xx2^(5)xx2^(2a))/(4xx2^(11a)xx2^(-2a))

Simplify (8^(3a)xx2^(5)xx2^(2a))/(4xx2^(11a)xx2^(-2a))

Evaluate : a. (-1)^(11) b. (-3)^(2)xx(5)^(3) c. 6^(2)xx3^(3) d. (-2)^(3)xx(-5)^(2) e. (-1)^(7)xx2 f. (-1)^(4)xx(-1)^(5) g. 4^(3)xx3^(4) h. (-2)^(5)xx5^(3) i. (-4)^(3)xx(-6)^(3) j. (-1)^(33)xx(-3)^(1) k. ((-1)/(6))^(2) l. ((2)/(11))^(3)

The sum of the infinite series (5)/(3^(2)xx7^(2))+(9)/(7^(2)xx11^(2))+(13)/(11^(2)xx15^(2))+... is

The sum (7)/(2^2xx5^2)+13/(5^2xx8^2)+19/(8^2xx11^2)+…10 terms is S, then the value of 1024(S) is __________.