If the surm of the first ten terms of the series,`(1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+........`, is `16/5m` ,then m is equal to

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to:

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to: (1) 102 (2) 101 (3) 100 (4) 99

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to: (1) 102 (2) 101 (3) 100 (4) 99

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to: (1) 102 (2) 101 (3) 100 (4) 99

If the sum of the first ten terms of the series (1(3)/(5))^(2)+(2(2)/(5))^(2)+(3(1)/(5))^(2)+4^(2)+(4(4)/(5))^(2)+.. is (16)/(5)m, then m is equal to: (1)102(2)101(3)100(4)99

If the sum of the first ten terms pf the series (1(3)/(5))^(2)+(2(2)/(5))^(2)+(3(1)/(5))^(2)+4^(2)+(4(4)/(5))^(2)....., "is " (16)/(5)m ,then m is equal to

The sum of the first n terms of the series 1^(2)+2.2^(2)+3^(2)+2.4^(2)+5^(2)+2.6^(2)+... is

The sum of n terms of the series 1^(2) - 2^(2) + 3^(2)- 4^(2) + 5^(2) -6^(2) + ….is

The sum of n terms of the series : (1)/( 1.2.3.4) + ( 1)/( 2.3.4.5) + ( 1) / ( 3.4.5.6.)+"......." is :