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From a point P two tangents are drawn to a circle with center o. if OP = diameter of the circle, show `triangleAPB` is equilateral.

Text Solution

Verified by Experts

In `triangle OAP`
OP=2r
`Sintheta=(OA)/(OP)=r/(2r)=1/2`
`sin theta=30^0`
`angleOPA=30^o`
similarly,
`angleOPB=30^o`
`angleAPB=angleOPA+angleOPB`
...
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