Let a,b,c be coordinates of vertices A,B,C of `DeltaABC`. [a,b,c are complec numbers]. If each of a,b,c are of unit modulus and there exists `alpha` such that `(a sec alpha) + b + ( c tan alpha)` = 0, `[ alpha in (o, pi/2)]`, Then area of the triangle `Delta ABC` can be

Let a,b,c be coordinates of vectices A,B,C of Delta ABC,[a,b,c are complex numbers.If each of a,b,c are unit modulus and exists alpha such that (a sec alpha)+b+(c tan alpha)=0,[alpha in(0,(pi)/(2))] then area of Delta ABC can be

In Delta ABC , prove that c cos (A - alpha) + a cos (C + alpha) = b cos alpha

In Delta ABC , prove that c cos (A - alpha) + a cos (C + alpha) = b cos alpha

In Delta ABC , prove that c cos (A - alpha) + a cos (C + alpha) = b cos alpha

In Delta ABC , prove that c cos (A - alpha) + a cos (C + alpha) = b cos alpha

If a alpha b and b alpha c , show that a^3+b^3+c^3 alpha 5 abc .

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha - d tan alpha=c , then eliminate alpha from above equations.

If Delta_(1) is the area of the triangle with vertices (0, 0), (a tan alpha, b cot alpha), (a sin alpha, b cos alpha), Delta_(2) is the area of the triangle with vertices (a sec^(2) alpha, b cos ec^(2) alpha), (a + a sin^(2)alpha, b + b cos^(2)alpha) and Delta_(3) is the area of the triangle with vertices (0,0), (a tan alpha, -b cot alpha), (a sin alpha, b cos alpha) . Show that there is no value of alpha for which Delta_(1), Delta_(2) and Delta_(3) are in GP.