2 mole , equimplar mixture of `Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) "required" V_(1) L of 0.1 M KMnO_(4)` in acidic medium for complete oxidation. The same amount of the mixture required ` V_(2) L of 0.2 M NaOH` for neutralisaation. The raation of ` V_(1) and V_(2)` is:

An equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_(1)L of 0.1 M KMnO_(4) in acidic medium for complete oxidation. The same amount of the mixture required V_(2)L of 0.1 M NaOH for neutralization. The ratio of V_(1) to V_(2) is

2 mole, equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_1 L of 0.1 M KMnO_4 in acidic medium for complete oxidatiion. The same amount of the mixture required V_2 L of 0.1 M NaOH for neutralization. The ratio of V_(1) " to "V_2 is x:y, then the value of x + y is (x and y are integers)

2 mole, equimolar mixture of Na_2C_2O_4 and H_2C_2O_4 required V_1L of 0.1MKMnO_4 in acidic medium for complete oxidation. The same amount of the mixture required V_2L of 0.2M NaOH for neutralization. The ratio of V_1 to V_2 is :

2 mole, equimolar mixture of Na_2C_2O_4 and H_2C_2O_4 required V_1L of 0.1MKHMO_4 in acidic medium for complete oxidation. The same amount of the mixture required V_2L of 0.2M NaOH for neutralization. The ratio of V_1 to V_2 is :

An equimolar mixture of Na_(2)C_(2)O_(4) and KHC_(2)O_(4)3H_(2)C_(2)O_(4) required V_(1) litre of 0.1MKMnO_(4) ion acidic medium for complete oxidation. The same amount of mixture required V_(2) litre of 0.2M NaOH for complete neutralization. What os the ratio of V_(1):V_(2) ?

1 mole of equimolar mixture of Fe_(2)(C_(2)O_(4))_(3) and FeC_(2)O_(4) required X moles of KMnO_(4) in acid medium for complete reaction. The value of X is:

1 mole of equimolar mixture of Fe_(2)(C_(2)O_(4))_(3) and FeC_(2)O_(4) required X moles of KMnO_(4) in acid medium for complete reaction. The value of X is:

1 mole of equimolar mixture of Fe_2(C_2O_4)_3 and FeC_2O_4 requires X mole of KMnO_4 In acid medium for complete oxidation. The value of X is