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Let alpha and beta are the roots of x^2 ...

Let `alpha and beta` are the roots of `x^2 – x – 1 = 0` such that `P_k = alpha^k + beta^k , k ge 1` then which one is incorrect?

A

`P_5 = P_3 xx P_2`

B

`P_1+P_2+P_3+P_4+P_5=26`

C

`P_3=P_5-P_4`

D

`P_5=11`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the values of \( P_k = \alpha^k + \beta^k \) for the roots \( \alpha \) and \( \beta \) of the equation \( x^2 - x - 1 = 0 \). ### Step 1: Find the roots \( \alpha \) and \( \beta \) The roots of the quadratic equation \( x^2 - x - 1 = 0 \) can be found using the quadratic formula: \[ \alpha, \beta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -1, c = -1 \): \[ \alpha, \beta = \frac{1 \pm \sqrt{1^2 - 4 \cdot 1 \cdot (-1)}}{2 \cdot 1} = \frac{1 \pm \sqrt{5}}{2} \] Thus, we have: \[ \alpha = \frac{1 + \sqrt{5}}{2}, \quad \beta = \frac{1 - \sqrt{5}}{2} \] ### Step 2: Calculate \( P_1 \) Using the definition of \( P_k \): \[ P_1 = \alpha^1 + \beta^1 = \alpha + \beta \] From Vieta's formulas, we know: \[ \alpha + \beta = 1 \] Thus, \[ P_1 = 1 \] ### Step 3: Calculate \( P_2 \) Using the relation \( P_k = \alpha^k + \beta^k \): \[ P_2 = \alpha^2 + \beta^2 \] Using the identity \( \alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta \): \[ \alpha\beta = -1 \quad \text{(from Vieta's)} \] So, \[ P_2 = 1^2 - 2(-1) = 1 + 2 = 3 \] ### Step 4: Calculate \( P_3 \) Using the recurrence relation \( P_k = P_{k-1} + P_{k-2} \): \[ P_3 = P_2 + P_1 = 3 + 1 = 4 \] ### Step 5: Calculate \( P_4 \) \[ P_4 = P_3 + P_2 = 4 + 3 = 7 \] ### Step 6: Calculate \( P_5 \) \[ P_5 = P_4 + P_3 = 7 + 4 = 11 \] ### Step 7: Check the options for correctness We have calculated: - \( P_1 = 1 \) - \( P_2 = 3 \) - \( P_3 = 4 \) - \( P_4 = 7 \) - \( P_5 = 11 \) Now, we check the statements given in the options. We need to find which one is incorrect. 1. **Check if \( P_5 = 11 \)**: Correct. 2. **Check if \( P_3 = 4 \)**: Correct. 3. **Check if \( P_4 + P_5 = 26 \)**: \( 7 + 11 = 18 \) (Incorrect). 4. **Check if \( 3P_3 = 12 \)**: \( 3 \times 4 = 12 \) (Correct). ### Conclusion The incorrect statement is the one that claims \( P_4 + P_5 = 26 \).

To solve the problem, we need to find the values of \( P_k = \alpha^k + \beta^k \) for the roots \( \alpha \) and \( \beta \) of the equation \( x^2 - x - 1 = 0 \). ### Step 1: Find the roots \( \alpha \) and \( \beta \) The roots of the quadratic equation \( x^2 - x - 1 = 0 \) can be found using the quadratic formula: \[ \alpha, \beta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -1, c = -1 \): ...
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