In a house 15 Bulbs of 45 W, 15 bulbs of 100 W, 15 bulbs of 10 W and Two heaters of 1 KW each is connected to 220 V Mains supply then find minimum fuse current

Options

A. 5A
B. 10A
C. 15A
D. 20A

Explanation

To find the minimum fuse current for the given electrical appliances in the house, we will follow these steps:

### Step 1: Calculate the total power consumed by all the bulbs and heaters.

1. **Power of 45 W bulbs**:
- Number of bulbs = 15
- Total power = 15 bulbs × 45 W/bulb = 675 W

2. **Power of 100 W bulbs**:
- Number of bulbs = 15
- Total power = 15 bulbs × 100 W/bulb = 1500 W

3. **Power of 10 W bulbs**:
- Number of bulbs = 15
- Total power = 15 bulbs × 10 W/bulb = 150 W

4. **Power of heaters**:
- Number of heaters = 2
- Power of each heater = 1 kW = 1000 W
- Total power = 2 heaters × 1000 W/heater = 2000 W

Now, we sum up all the powers:
\[ \text{Total Power} = 675 W + 1500 W + 150 W + 2000 W = 4325 W \]

### Step 2: Use the formula to calculate current.

The formula relating power (P), voltage (V), and current (I) is:
\[ P = V \times I \]
Rearranging this gives:
\[ I = \frac{P}{V} \]

### Step 3: Substitute the known values into the equation.

Given:
- Total Power (P) = 4325 W
- Voltage (V) = 220 V

Substituting these values:
\[ I = \frac{4325 W}{220 V} \]

### Step 4: Calculate the current.

Now, performing the division:
\[ I = \frac{4325}{220} \approx 19.66 A \]

### Step 5: Round up to find the minimum fuse current.

Since fuses are rated in whole numbers, we round 19.66 A up to the nearest whole number:
\[ \text{Minimum Fuse Current} \approx 20 A \]

### Final Answer:
The minimum fuse current required is **20 A**.

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