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Find the dimension of B^2/(2 mu0)...

Find the dimension of `B^2/(2 mu_0)`

A

`M L^(-2) T^(-2)`

B

`M L^(2) T^(-1)`

C

`M L^(-1) T^(-2)`

D

None of These

Text Solution

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The correct Answer is:
C
NA
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The dimension of (B^(2))/(2mu_(0)), where B is magnetic field and mu_(0) is the magnetic permeability of vacuum, is :

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Knowledge Check

  • The dimensions of mu_(0) are

    A
    `[M^(1)L^(-1//2)T^(1//2)]`
    B
    `[M^(1)L^(1//2)T^(-1//2)]`
    C
    `[L^(-1)T]`
    D
    `[M^(1)L^(1)T^(-2)A^(-2)]`

  • Find the dimension of epsilon_(0)E^(2) , where epsilon_(0) is permittivity of free space and E is the electricity field

    A
    `[M^(1) L^(1) T^(-2) A^(1)]`
    B
    `[M^(1) L^(0)T^(-1)]`
    C
    `[M^(1) L^(-1) T^(-2) A^(1)]`
    D
    `[M^(1) L^(-1) T^(-2)]`

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