Molar conductivity of aqueous solution of `HA` is `200Scm^(2)mol^(-1),pH` of this solution is `4`
Calculate the value of `pK_(a)(HA)` at `25^(@)C`.
Given `^^_(M)^(oo)(NaA)=100scm^(2)mol^(-1),`
`^^_(M)^(oo)(HCl)=425Scm^(2)mol^(-1),`
`^^_(M)^(oo)(NaCl)=125 Scm^(2)mol^(-1)`

Molar conductivity of aqueous solution of HA is 200 S cm^(2) "mol"^(-1) , pH of this solution is 4. Calculate the value of pK_(a) (HA) at 25^(@) C Given: wedge_(M)^(infty) (NaA) = 100 S cm^(2) mol^(-1), wedge_(M)^(infty)(HCl)= 425 Scm^(2) "mol"^(-1) , wedge_(M)^(infty)(NaCl) = 125 Scm^(2)"mol"^(-1) .

Calculate Lambda_(m)^(oo) for acetic acid, given, Lambda_(m)^(oo)(HCl)=426 Omega^(-1)cm^(2)mol^(-1),Lambda_(m)^(oo)(NaCl)=126Omega^(-1)cm^(2)mol^(-1) , Lambda_(m)^(oo)(CHCOONa)=91Omega^(-1)cm^(2)mol^(-1)

The molar conductivity of 0.25 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Calculate the degree of dissociation constant. Given : lambda_((H^(o+)))^(@)=349.6S cm^(2)mol^(-1) and lambda_(HCOO^(-))^(@)=54.6Scm^(2)mol^(-1)

At 298K the conductivity of a saturated solution of AgCl in water is 2.6times10^(-6)Scm^(-1) .Its solubility product at 298K (given : lambda^(oo) ( Ag^(+) )=63.0 Scm^(2)mol^(-1) lambda^(oo) (Cl^(-)) =67.0 Scm^(2)mol^(-1) )

The conductivity of 0.20M solution of KCL at 298K is 0.0248Scm^-1 , Calculate its molar conductivity.

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1) . Calculate the molar conductivity of the KCl solution.

Conductivity of an aqueous solution of 0.1M HX (a weak mono-protic acid) is 5 xx 10^(-4) Sm^(-1) Given: ^^_(m)^(oo) [H^(+)] = 0.04 Sm^(2) mol^(-1): ^^_(m)^(oo) [X^(-)] = 0.01 Sm^(2)mol^(-1) Find pK_(a)[HX]