[f(x)=e^(ix tan^(-x))tan x],[f''(x)=?]

If f(x)=x*tan^(-1)x," then: "f'(1)=

If f(x)=x tan^(-1)x, then f'(1) equals

If : f(x)=x*tan^(-1)x," then: "f'(1)=

If f(x)=tan^(-1)x , then find f''(x).

Let f(x)=(e^(tan x)-e^(x)+ln(sec x+tan x)-x)/(tan x-x) be a continuous function at x=0. The value f(0) equals

If f(x) = log (tan x), then f^(')(x) =

If f(x) is continuous at x=0 , where f(x)=(sin (a+x)-sin (a-x))/(tan (a+x)-tan (a-x)), x != 0 , then f(0)=

If f(x)=(x+1)tan^(-1)(e^(-2x)) , then f'(0) is

If f(x)=(x+1)tan^(-1)(e^(-2x)) , then f'(0) is