Arithmetic mean = (sum of all observations)/(Number of observations)

The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

Assertion : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then mean of last three observations is 8. Reason : Mean of n observations is equal to Sum of observations upon Number of observations

The arithmetic mean of 13 observations is 60. If one of the observation 50 is deleted and another observation 63 is included. Find the new arithmetic mean. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) New sum of observations =780-50+63=793 (B) The sum of the observation =13xx60=780 (C) :. New arithmetic mean =793/13 (D) The required mean =61

The mean of 36 observations is 22.If one observation 22 is deleted ,then find the new mean The following steps are involved in solving the above problem .Arrange then in sequential order . therefore New arithmetic mean =770/35 = 22 ( B) Arithemetic mean ="The sum of the observations "/"Total number of the observations" rArr 22 ="The sum of the observations "/36 ( C) The sum of the observations 22 is deleted , the new sum = 792 -22 = 770 and the number of observations is 36 -1 ,i.e 35,.

The arithmetic mean of a set of observations is bar(X) . If each observation is divided by alpha and then is increased by 10, then the mean of the new series is

The mean of a data is 15 and the sum of the observations is 195. The number of observations is 13 (b) 19 16 (d) 17