The time period of revolution of moon around the earth is 28 days and radius of its orbit is `4xx10^(5)` km. If `G=6.67xx10^(-11) Nm^(2)//kg^(2)` then find the mass of the earth.

The period of moon around the earth is 27.3 days and radius of the orbit is 3.9 xx 10^(5) km . G=6.67 xx 10^(-11) Nm^(-2)kg^(-2) , find the mass of the earth.

Find the mass of the earth from the following data. The period of lunar orbit around the earth is 27.3 days and radius of the orbit 3.9 xx 10^(5) km. G = 6.67 xx 10^(-11) Nm^(-2) kg^(-2) .

Calculate the mass of sun if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

The distance between centre of the earth and moon is 384000 km . If the mass of the earth is 6xx10^(24) kg and G=6.66xx10^(-11)Nm^(2)//kg^(2) . The speed of the moon is nearly

An artificial satellite revolves round the earth at a height of 1000 km . The radius of the earth is 6.38xx10^(3)km . Mass of the earth 6xx10^(24)kg,G=6.67xx10^(-11)Nm^(2)kg^(-2) . Find the orbital speed and period of revolution of the satellite.