The sum of n terms of two arithmetic progression is in the ratio 2n+1 : 2n-1. Find the ratio of `10^th` term.

Explanation

Let first term in first AP is `a_1` and common difference is `d_1`.

Let first term in second AP is `a_2` and common difference is `d_2`.

Then, we are given,

`S_1/S_2 = (2n+1)/(2n-1)`

`(n/2(2a_1+(n-1)d_1))/(n/2(2a_2+(n-1)d_2)) = (2n+1)/(2n-1)`

`=>(2a_1+(n-1)d_1)/(2a_2+(n-1)d_2) = (2n+1)/(2n-1)->(1)`

Now, we have to find ratio of `10th ` terms of both AP.

If we put `n = 19` in (1),

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